:: BORSUK_3 semantic presentation
theorem Th1: :: BORSUK_3:1
theorem Th2: :: BORSUK_3:2
Lemma3:
for b1 being non empty TopStruct holds b1,b1 are_homeomorphic
Lemma4:
for b1, b2 being non empty TopStruct holds
( b1,b2 are_homeomorphic implies b2,b1 are_homeomorphic )
theorem Th3: :: BORSUK_3:3
proof
let c
1, c
2, c
3 be non
empty TopSpace;
assume E5:
( c
1,c
2 are_homeomorphic & c
2,c
3 are_homeomorphic )
;
then consider c
4 being
Function of c
1,c
2 such that E6:
c
4 is_homeomorphism
by T_0TOPSP:def 1;
consider c
5 being
Function of c
2,c
3 such that E7:
c
5 is_homeomorphism
by E5, T_0TOPSP:def 1;
c
5 * c
4 is_homeomorphism
by E6, E7, TOPS_2:71;
hence
c
1,c
3 are_homeomorphic
by T_0TOPSP:def 1;
end;
theorem Th4: :: BORSUK_3:4
theorem Th5: :: BORSUK_3:5
theorem Th6: :: BORSUK_3:6
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:c2,(c1 | {c3}):],c
2;
set c
5 =
{c3};
assume E8:
c
4 = pr1 the
carrier of c
2,
{c3}
;
then E9:
dom c
4 = [:the carrier of c2,{c3}:]
by FUNCT_3:def 5;
let c
6, c
7 be
set ;
:: according to FUNCT_1:def 8
assume that E10:
( c
6 in dom c
4 & c
7 in dom c
4 )
and E11:
c
4 . c
6 = c
4 . c
7
;
consider c
8, c
9 being
set such that E12:
( c
8 in the
carrier of c
2 & c
9 in {c3} & c
6 = [c8,c9] )
by E9, E10, ZFMISC_1:def 2;
consider c
10, c
11 being
set such that E13:
( c
10 in the
carrier of c
2 & c
11 in {c3} & c
7 = [c10,c11] )
by E9, E10, ZFMISC_1:def 2;
E14: c
9 =
c
3
by E12, TARSKI:def 1
.=
c
11
by E13, TARSKI:def 1
;
c
8 =
c
4 . [c10,c11]
by E8, E11, E12, E13, FUNCT_3:def 5
.=
c
10
by E8, E13, FUNCT_3:def 5
;
hence
c
6 = c
7
by E12, E13, E14;
end;
theorem Th7: :: BORSUK_3:7
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:(c1 | {c3}),c2:],c
2;
set c
5 =
{c3};
assume E9:
c
4 = pr2 {c3},the
carrier of c
2
;
then E10:
dom c
4 = [:{c3},the carrier of c2:]
by FUNCT_3:def 6;
let c
6, c
7 be
set ;
:: according to FUNCT_1:def 8
assume that E11:
( c
6 in dom c
4 & c
7 in dom c
4 )
and E12:
c
4 . c
6 = c
4 . c
7
;
consider c
8, c
9 being
set such that E13:
( c
8 in {c3} & c
9 in the
carrier of c
2 & c
6 = [c8,c9] )
by E10, E11, ZFMISC_1:def 2;
consider c
10, c
11 being
set such that E14:
( c
10 in {c3} & c
11 in the
carrier of c
2 & c
7 = [c10,c11] )
by E10, E11, ZFMISC_1:def 2;
E15: c
8 =
c
3
by E13, TARSKI:def 1
.=
c
10
by E14, TARSKI:def 1
;
c
9 =
c
4 . [c10,c11]
by E9, E12, E13, E14, FUNCT_3:def 6
.=
c
11
by E9, E14, FUNCT_3:def 6
;
hence
c
6 = c
7
by E13, E14, E15;
end;
theorem Th8: :: BORSUK_3:8
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:c2,(c1 | {c3}):],c
2;
set c
5 =
{c3};
assume E10:
c
4 = pr1 the
carrier of c
2,
{c3}
;
then E11:
rng c
4 =
the
carrier of c
2
by FUNCT_3:60
.=
[#] c
2
by PRE_TOPC:12
;
E12:
c
4 is
one-to-one
by E10, Th6;
reconsider c
6 =
{c3} as non
empty Subset of c
1 ;
reconsider c
7 = c
2 --> c
3 as
continuous Function of c
2,
(c1 | c6) by Th2;
set c
8 =
id c
2;
reconsider c
9 =
<:(id c2),c7:> as
continuous Function of c
2,
[:c2,(c1 | c6):] by YELLOW12:41;
E13:
rng c
9 c= [:(rng (id c2)),(rng c7):]
by FUNCT_3:71;
rng c
7 c= the
carrier of
(c1 | c6)
;
then E14:
rng c
7 c= c
6
by PRE_TOPC:29;
[:(rng (id c2)),(rng c7):] c= [:the carrier of c2,c6:]
by E14, ZFMISC_1:119;
then E15:
rng c
9 c= [:the carrier of c2,c6:]
by E13, XBOOLE_1:1;
[:the carrier of c2,c6:] c= rng c
9
proof
let c
10 be
set ;
:: according to TARSKI:def 3
assume
c
10 in [:the carrier of c2,c6:]
;
then consider c
11, c
12 being
set such that E16:
( c
11 in the
carrier of c
2 & c
12 in {c3} & c
10 = [c11,c12] )
by ZFMISC_1:def 2;
E17:
c
10 = [c11,c3]
by E16, TARSKI:def 1;
E18: c
7 . c
11 =
(the carrier of c2 --> c3) . c
11
by BORSUK_1:def 2
.=
c
3
by E16, FUNCOP_1:13
;
E19:
c
11 in dom c
9
by E16, FUNCT_2:def 1;
then c
9 . c
11 =
[((id c2) . c11),(c7 . c11)]
by FUNCT_3:def 8
.=
[c11,c3]
by E16, E18, FUNCT_1:35
;
hence
c
10 in rng c
9
by E17, E19, FUNCT_1:def 5;
end;
then E16:
rng c
9 =
[:the carrier of c2,c6:]
by E15, XBOOLE_0:def 10
.=
dom c
4
by E10, FUNCT_3:def 5
;
E17:
dom c
7 =
the
carrier of c
2
by FUNCT_2:def 1
.=
dom (id c2)
by FUNCT_2:def 1
;
rng (id c2) c= the
carrier of c
2
;
then c
4 * c
9 =
id c
2
by E10, E14, E17, FUNCT_3:72
.=
id the
carrier of c
2
.=
id (rng c4)
by E11, PRE_TOPC:12
;
then
c
9 = c
4 "
by E12, E16, FUNCT_1:64;
hence
c
4 " = <:(id c2),(c2 --> c3):>
by E11, E12, TOPS_2:def 4;
end;
theorem Th9: :: BORSUK_3:9
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:(c1 | {c3}),c2:],c
2;
set c
5 =
{c3};
assume E11:
c
4 = pr2 {c3},the
carrier of c
2
;
then E12:
rng c
4 =
the
carrier of c
2
by FUNCT_3:62
.=
[#] c
2
by PRE_TOPC:12
;
E13:
c
4 is
one-to-one
by E11, Th7;
reconsider c
6 =
{c3} as non
empty Subset of c
1 ;
reconsider c
7 = c
2 --> c
3 as
continuous Function of c
2,
(c1 | c6) by Th2;
set c
8 =
id c
2;
reconsider c
9 =
<:c7,(id c2):> as
continuous Function of c
2,
[:(c1 | c6),c2:] by YELLOW12:41;
E14:
rng c
9 c= [:(rng c7),(rng (id c2)):]
by FUNCT_3:71;
rng c
7 c= the
carrier of
(c1 | c6)
;
then E15:
rng c
7 c= c
6
by PRE_TOPC:29;
[:(rng c7),(rng (id c2)):] c= [:{c3},the carrier of c2:]
by E15, ZFMISC_1:119;
then E16:
rng c
9 c= [:{c3},the carrier of c2:]
by E14, XBOOLE_1:1;
[:{c3},the carrier of c2:] c= rng c
9
proof
let c
10 be
set ;
:: according to TARSKI:def 3
assume
c
10 in [:{c3},the carrier of c2:]
;
then consider c
11, c
12 being
set such that E17:
( c
11 in {c3} & c
12 in the
carrier of c
2 & c
10 = [c11,c12] )
by ZFMISC_1:def 2;
E18:
c
10 = [c3,c12]
by E17, TARSKI:def 1;
E19: c
7 . c
12 =
(the carrier of c2 --> c3) . c
12
by BORSUK_1:def 2
.=
c
3
by E17, FUNCOP_1:13
;
E20:
c
12 in dom c
9
by E17, FUNCT_2:def 1;
then c
9 . c
12 =
[(c7 . c12),((id c2) . c12)]
by FUNCT_3:def 8
.=
[c3,c12]
by E17, E19, FUNCT_1:35
;
hence
c
10 in rng c
9
by E18, E20, FUNCT_1:def 5;
end;
then E17:
rng c
9 =
[:c6,the carrier of c2:]
by E16, XBOOLE_0:def 10
.=
dom c
4
by E11, FUNCT_3:def 6
;
E18:
dom c
7 =
the
carrier of c
2
by FUNCT_2:def 1
.=
dom (id c2)
by FUNCT_2:def 1
;
rng (id c2) c= the
carrier of c
2
;
then c
4 * c
9 =
id c
2
by E11, E15, E18, FUNCT_3:72
.=
id the
carrier of c
2
.=
id (rng c4)
by E12, PRE_TOPC:12
;
then
c
9 = c
4 "
by E13, E17, FUNCT_1:64;
hence
c
4 " = <:(c2 --> c3),(id c2):>
by E12, E13, TOPS_2:def 4;
end;
theorem Th10: :: BORSUK_3:10
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:c2,(c1 | {c3}):],c
2;
set c
5 =
{c3};
assume E11:
c
4 = pr1 the
carrier of c
2,
{c3}
;
E12:
the
carrier of
(c1 | {c3}) = {c3}
by PRE_TOPC:29;
thus dom c
4 =
the
carrier of
[:c2,(c1 | {c3}):]
by FUNCT_2:def 1
.=
[#] [:c2,(c1 | {c3}):]
by PRE_TOPC:12
;
:: according to TOPS_2:def 5
thus rng c
4 =
the
carrier of c
2
by E11, FUNCT_3:60
.=
[#] c
2
by PRE_TOPC:12
;
thus
c
4 is
one-to-one
by E11, Th6;
thus
c
4 is
continuous
by E11, E12, YELLOW12:39;
reconsider c
6 =
{c3} as non
empty Subset of c
1 ;
reconsider c
7 = c
2 --> c
3 as
continuous Function of c
2,
(c1 | c6) by Th2;
reconsider c
8 =
<:(id c2),c7:> as
continuous Function of c
2,
[:c2,(c1 | c6):] by YELLOW12:41;
c
8 = c
4 "
by E11, Th8;
hence
c
4 " is
continuous
;
end;
theorem Th11: :: BORSUK_3:11
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be
Function of
[:(c1 | {c3}),c2:],c
2;
set c
5 =
{c3};
assume E12:
c
4 = pr2 {c3},the
carrier of c
2
;
E13:
the
carrier of
(c1 | {c3}) = {c3}
by PRE_TOPC:29;
thus dom c
4 =
the
carrier of
[:(c1 | {c3}),c2:]
by FUNCT_2:def 1
.=
[#] [:(c1 | {c3}),c2:]
by PRE_TOPC:12
;
:: according to TOPS_2:def 5
thus rng c
4 =
the
carrier of c
2
by E12, FUNCT_3:62
.=
[#] c
2
by PRE_TOPC:12
;
thus
c
4 is
one-to-one
by E12, Th7;
thus
c
4 is
continuous
by E12, E13, YELLOW12:40;
reconsider c
6 =
{c3} as non
empty Subset of c
1 ;
reconsider c
7 = c
2 --> c
3 as
continuous Function of c
2,
(c1 | c6) by Th2;
reconsider c
8 =
<:c7,(id c2):> as
continuous Function of c
2,
[:(c1 | c6),c2:] by YELLOW12:41;
c
8 = c
4 "
by E12, Th9;
hence
c
4 " is
continuous
;
end;
theorem Th12: :: BORSUK_3:12
proof
let c
1 be non
empty TopSpace;
let c
2 be non
empty compact TopSpace;
let c
3 be
open Subset of
[:c1,c2:];
let c
4 be
set ;
assume
c
4 in { b1 where B is Point of c1 : [:{b1},the carrier of c2:] c= c3 }
;
then consider c
5 being
Point of c
1 such that E12:
( c
4 = c
5 &
[:{c5},the carrier of c2:] c= c
3 )
;
E13:
[:{c5},the carrier of c2:] c= union (Base-Appr c3)
by E12, BORSUK_1:54;
E14:
now
let c
6 be
set ;
assume E15:
c
6 in the
carrier of c
2
;
c
4 in {c5}
by E12, TARSKI:def 1;
then
[c4,c6] in [:{c5},the carrier of c2:]
by E15, ZFMISC_1:106;
then consider c
7 being
set such that E16:
(
[c4,c6] in c
7 & c
7 in Base-Appr c
3 )
by E13, TARSKI:def 4;
Base-Appr c
3 = { [:b1,b2:] where B is Subset of c1, B is Subset of c2 : ( [:b1,b2:] c= c3 & b1 is open & b2 is open ) }
by BORSUK_1:def 6;
then consider c
8 being
Subset of c
1, c
9 being
Subset of c
2 such that E17:
( c
7 = [:c8,c9:] &
[:c8,c9:] c= c
3 & c
8 is
open & c
9 is
open )
by E16;
thus
ex b
1 being
Subset of c
1ex b
2 being
Subset of c
2 st
(
[c4,c6] in [:b1,b2:] &
[:b1,b2:] c= c
3 & b
1 is
open & b
2 is
open )
by E16, E17;
end;
defpred S
1[
set ,
set ] means ex b
1 being
Subset of c
1ex b
2 being
Subset of c
2 st
( a
2 = [b1,b2] &
[c4,a1] in [:b1,b2:] & b
1 is
open & b
2 is
open &
[:b1,b2:] c= c
3 );
E15:
for b
1 being
set holds
not ( b
1 in the
carrier of c
2 & ( for b
2 being
set holds
not S
1[b
1,b
2] ) )
proof
let c
6 be
set ;
assume
c
6 in the
carrier of c
2
;
then consider c
7 being
Subset of c
1, c
8 being
Subset of c
2 such that E16:
(
[c4,c6] in [:c7,c8:] &
[:c7,c8:] c= c
3 & c
7 is
open & c
8 is
open )
by E14;
ex b
1 being
Subset of c
1ex b
2 being
Subset of c
2 st
(
[c7,c8] = [b1,b2] &
[c4,c6] in [:b1,b2:] & b
1 is
open & b
2 is
open &
[:b1,b2:] c= c
3 )
by E16;
hence
ex b
1 being
set st
S
1[c
6,b
1]
;
end;
ex b
1 being
ManySortedSet of the
carrier of c
2 st
for b
2 being
set holds
( b
2 in the
carrier of c
2 implies S
1[b
2,b
1 . b
2] )
from PBOOLE:sch 3(E15);
hence
ex b
1 being
ManySortedSet of the
carrier of c
2 st
for b
2 being
set holds
not ( b
2 in the
carrier of c
2 & ( for b
3 being
Subset of c
1for b
4 being
Subset of c
2 holds
not ( b
1 . b
2 = [b3,b4] &
[c4,b2] in [:b3,b4:] & b
3 is
open & b
4 is
open &
[:b3,b4:] c= c
3 ) ) )
;
end;
theorem Th13: :: BORSUK_3:13
proof
let c
1 be non
empty TopSpace;
let c
2 be non
empty compact TopSpace;
let c
3 be
open Subset of
[:c2,c1:];
let c
4 be
set ;
assume
c
4 in { b1 where B is Point of c1 : [:([#] c2),{b1}:] c= c3 }
;
then consider c
5 being
Point of c
1 such that E13:
( c
5 = c
4 &
[:([#] c2),{c5}:] c= c
3 )
;
E14:
[#] c
2 is
compact
by COMPTS_1:10;
Int c
3 = c
3
by TOPS_1:55;
then
c
3 is
a_neighborhood of
[:([#] c2),{c5}:]
by E13, CONNSP_2:def 2;
then consider c
6 being
a_neighborhood of
[#] c
2, c
7 being
a_neighborhood of c
5 such that E15:
[:c6,c7:] c= c
3
by E14, BORSUK_1:67;
take c
8 =
Int c
7;
E16:
(
Int c
6 c= c
6 &
Int c
7 c= c
7 )
by TOPS_1:44;
[#] c
2 c= Int c
6
by CONNSP_2:def 2;
then E17:
[#] c
2 c= c
6
by E16, XBOOLE_1:1;
c
8 c= { b1 where B is Point of c1 : [:([#] c2),{b1}:] c= c3 }
hence
( c
4 in c
8 & c
8 c= { b1 where B is Point of c1 : [:([#] c2),{b1}:] c= c3 } )
by E13, CONNSP_2:def 1;
end;
theorem Th14: :: BORSUK_3:14
theorem Th15: :: BORSUK_3:15
Lemma15:
for b1, b2 being non empty TopSpace
for b3 being Point of b1
for b4 being non empty Subset of b1 holds
( b4 = {b3} implies [:b2,(b1 | b4):],b2 are_homeomorphic )
proof
let c
1, c
2 be non
empty TopSpace;
let c
3 be
Point of c
1;
let c
4 be non
empty Subset of c
1;
assume
c
4 = {c3}
;
then E16:
[:(c1 | c4),c2:],c
2 are_homeomorphic
by Th15;
E17:
[:c2,(c1 | c4):],
[:(c1 | c4),c2:] are_homeomorphic
by YELLOW12:44;
consider c
5 being
Function of
[:(c1 | c4),c2:],c
2 such that E18:
c
5 is_homeomorphism
by E16, T_0TOPSP:def 1;
consider c
6 being
Function of
[:c2,(c1 | c4):],
[:(c1 | c4),c2:] such that E19:
c
6 is_homeomorphism
by E17, T_0TOPSP:def 1;
reconsider c
7 = c
5 * c
6 as
Function of
[:c2,(c1 | c4):],c
2 ;
c
7 is_homeomorphism
by E18, E19, TOPS_2:71;
hence
[:c2,(c1 | c4):],c
2 are_homeomorphic
by T_0TOPSP:def 1;
end;
theorem Th16: :: BORSUK_3:16